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Axew763's Blog: The world hates me.
I posted my cyberbullying story on Tumblr, and I got even more hate comments. People hate me. I’m thinking about leaving Tumblr, actually. Seriously, world, I am a person with feelings, and everybody thinks…
hai carrie, ai herd ur sooper smart (sbs sez u h as an iq of 167!!) thts awsum!1! ur lyk da smartestest persn i kno bai a LOT!1 nd i’v met conway and tao…
so neway im in 6th grade nd ai just turnd 12, nd i reeely need this problem solved:
Find the last two digits of 56^(8754^689105482513)
mai parentz wont give meh my birfday prezent until ai solve it :’(
sew this is wut i has so far: i get tht u use da chniese remaindr theorem to simplefy it 2 56^(8754^689105482513) (mod 25) and 56^(8754^689105482513) (mod 4) nd then becuz 56 is eben thts 0 mod 4, nd in mod 25u use da totient funcshun to get 6^20=1 (mod 25) nd then since 8754^689105482513=(-6)^689105482513 (mod 20) nd 4 all q>1, (-6)^q=(-4)(-1)^q, so 8754^689105482513=4 mod 20
nd then u get 56^(8754^689105482513)=6^4 (mod 25)=-4 mod 25
but wut do u do from dere? HALP ai went thru ebery single numba and ai couldnt find 1 tht wuz 0 mod 4 and -4 mod 25 …. HALP!1!!??? :’( ai reeeeely want a prezent… i kno itz reeely elimentry numba theoreee nd i lernd it last yr but i forgotz it, sorreh
(Source: sassy-gay-nordics, via sassy-gay-nordics)
